Python Set intersection_update() Method
Example
Remove the items that is not present in both x
and y:
x =
{"apple", "banana", "cherry"}
y = {"google",
"microsoft", "apple"}
x.intersection_update(y)
print(x)
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Definition and Usage
The intersection_update() method removes the
items that is not present in both sets (or in all sets if the comparison is done
between more than two sets).
The intersection_update() method is different
from the intersection() method, because the
intersection()
method returns a new set, without the unwanted items, and the
intersection_update() method removes the
unwanted items from the original set.
As a shortcut, you can use the &= operator instead, see example below.
Syntax
set.intersection_update(set1, set2 ... etc)
Parameter Values
| Parameter | Description |
|---|---|
| set1 | Required. The set to search for equal items in |
| set2 | Optional. The other set to search for equal items in. You can compare as many sets you like. Separate the sets with a comma |
Shorter Syntax
set &= set1 & set2 ... etc.
Parameter Values
| Parameter | Description |
|---|---|
| set1 | Required. The set to search for equal items in |
| set2 | Optional. The other set to search for equal items in. You can compare as many sets you like. Separate the sets with &
(a and operator).See examples below. |
More Examples
Example
Use &= as a shortcut instead of
intersection_update():
x =
{"apple", "banana", "cherry"}
y = {"google",
"microsoft", "apple"}
x &= y
print(x)
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Example
Compare 3 sets, and return a set with items that is present in all 3 sets:
x =
{"a", "b", "c"}
y = {"c",
"d", "e"}
z = {"f",
"g", "c"}
x.intersection_update(y, z)
print(x)
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Example
Join 3 sets with the &= operator:
x =
{"a", "b", "c"}
y = {"c",
"d", "e"}
z = {"f",
"g", "c"}
x &= y & z
print(result)
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