MySQL HAVING Clause
The MySQL HAVING Clause
The HAVING clause is used to filter the results of a GROUP BY query based on aggregate functions.
Unlike the WHERE clause, which filters individual rows before grouping,
the HAVING
clause
filters groups after the aggregation has been performed.
HAVING Syntax
SELECT column1, aggregate_function(column2), column3, ...
FROM table_name
WHERE condition
GROUP BY column1, column3
HAVING condition -- The condition on grouped data
ORDER BY column_name;Demo Database
Below is a selection from the "Customers" table in the Northwind sample database:
| CustomerID | CustomerName | ContactName | Address | City | PostalCode | Country |
|---|---|---|---|---|---|---|
| 1 |
Alfreds Futterkiste | Maria Anders | Obere Str. 57 | Berlin | 12209 | Germany |
| 2 | Ana Trujillo Emparedados y helados | Ana Trujillo | Avda. de la Constitución 2222 | México D.F. | 05021 | Mexico |
| 3 | Antonio Moreno Taquería | Antonio Moreno | Mataderos 2312 | México D.F. | 05023 | Mexico |
| 4 |
Around the Horn | Thomas Hardy | 120 Hanover Sq. | London | WA1 1DP | UK |
| 5 | Berglunds snabbköp | Christina Berglund | Berguvsvägen 8 | Luleå | S-958 22 | Sweden |
MySQL HAVING Examples
The following SQL returns the number of customers in each country - but only include countries with more than 5 customers:
Example
SELECT Country, COUNT(CustomerID) AS "Number of Customers"
FROM Customers
GROUP BY Country
HAVING COUNT(CustomerID) > 5;
Try it Yourself »
The following SQL returns the number of customers in each country, sorted from high to low (and only include countries with more than 5 customers):
Example
SELECT Country, COUNT(CustomerID) AS "Number of Customers"
FROM Customers
GROUP BY Country
HAVING COUNT(CustomerID)
> 5
ORDER BY COUNT(CustomerID) DESC;
Try it Yourself »
Demo Database
Below is a selection from the "Orders" table in the Northwind sample database:
| OrderID | CustomerID | EmployeeID | OrderDate | ShipperID |
|---|---|---|---|---|
| 10248 | 90 | 5 | 1996-07-04 | 3 |
| 10249 | 81 | 6 | 1996-07-05 | 1 |
| 10250 | 34 | 4 | 1996-07-08 | 2 |
And a selection from the "Employees" table:
| EmployeeID | LastName | FirstName | BirthDate | Photo | Notes |
|---|---|---|---|---|---|
| 1 | Davolio | Nancy | 1968-12-08 | EmpID1.pic | Education includes a BA.... |
| 2 | Fuller | Andrew | 1952-02-19 | EmpID2.pic | Andrew received his BTS.... |
| 3 | Leverling | Janet | 1963-08-30 | EmpID3.pic | Janet has a BS degree.... |
More HAVING Examples
The following SQL returns the employees that have registered more than 10 orders:
Example
SELECT Employees.LastName, COUNT(Orders.OrderID) AS NumberOfOrders
FROM
(Orders
INNER JOIN Employees ON Orders.EmployeeID = Employees.EmployeeID)
GROUP BY LastName
HAVING COUNT(Orders.OrderID) > 10;
Try it Yourself »
The following SQL returns if the employees "Davolio" or "Fuller" have registered more than 25 orders:
Example
SELECT Employees.LastName, COUNT(Orders.OrderID) AS NumberOfOrders
FROM Orders
INNER JOIN Employees ON Orders.EmployeeID = Employees.EmployeeID
WHERE LastName = 'Davolio' OR LastName = 'Fuller'
GROUP BY LastName
HAVING
COUNT(Orders.OrderID) > 25;
Try it Yourself »
